Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 550: 69

Answer

$\frac{\sqrt {2nm}}{2m}$.

Work Step by Step

The given expression is $=\sqrt {\frac{7m^2n^3}{14m^3n^2}}$ Simplify. $=\sqrt {\frac{m^2n^3}{2m^3n^2}}$ Use the quotient rule and rewrite as the quotient of radicals. $=\frac{\sqrt {m^2n^3}}{\sqrt {2m^3n^2}}$ Divide factors in the radicand. Subtract exponents on common bases. $=\frac{\sqrt {n^{3-2}}}{\sqrt {2m^{3-2}}}$ Simplify. $=\frac{\sqrt {n}}{\sqrt {2m}}$ Multiply the numerator and denominator by $\sqrt{2m}$. $=\frac{\sqrt {n}}{\sqrt {2m}}\cdot \frac{\sqrt {2m}}{\sqrt {2m}}$ Multiply. $=\frac{\sqrt {n\cdot 2m}}{\sqrt {(2m)^2}}$ Simplify. $=\frac{\sqrt {2nm}}{2m}$.
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