Answer
$\dfrac{4\sqrt[3]{x^2}}{x}$
Work Step by Step
RECALL:
For any real number $a$,
$\sqrt[3]{a^3}= a$
Rationalize the denominator by multiplying $\sqrt[3]{x^2}$ to both the numerator and the denominator.
Simplify using the rule above to obtain:
$\require{cancel}
=\dfrac{4 \cdot \sqrt[3]{x^2}}{\sqrt[3]{x} \cdot \sqrt[3]{x^2}}
\\=\dfrac{4\sqrt[3]{x^2}}{\sqrt[3]{x^3}}
\\=\dfrac{4\sqrt[3]{x^2}}{x}$
