Answer
$\frac{1}{3}\sqrt[3]{18}$
Work Step by Step
RECALL:
For any real number $a$,
$\sqrt[3]{a^3}= a$
Rationalize the denominator by multiplying $3^2$ to both the numerator and the denominator of the radicand.
Simplify using the rule above to obtain:
$\require{cancel}
=\sqrt[3]{\dfrac{2(3^2)}{3(3^2)}}
\\=\sqrt[3]{\dfrac{2(9)}{3^3}}
\\=\frac{1}{3}\sqrt[3]{18}$
