Answer
$\dfrac{\sqrt[3]{2y}}{y}$
Work Step by Step
RECALL:
For any real number $a$,
$\sqrt[3]{a^3}= a$
Rationalize the denominator by multiplying $y$ to both the numerator and the denominator of the radicand.
Simplify using the rule above to obtain:
$\require{cancel}
=\sqrt{\dfrac{2(y)}{y^2(y)}}
\\=\sqrt{\dfrac{2y}{y^3}}
\\=\frac{1}{y} \cdot \sqrt[3]{2y}
\\=\dfrac{\sqrt[3]{2y}}{y}$
