Answer
$\dfrac{\sqrt[3]{9}}{3}$
Work Step by Step
RECALL:
For any real number $a$,
$\sqrt[3]{a^3}= a$
Rationalize the denominator by multiplying $\sqrt[3]{3^2}$ to both the numerator and the denominator. Simplify using the rule above to obtain:
$\require{cancel}
=\dfrac{1 \cdot \sqrt[3]{3^2}}{\sqrt[3]{3} \cdot \sqrt[3]{3^2}}
\\=\dfrac{\sqrt[3]{3^2}}{\sqrt[3]{3^3}}
\\=\dfrac{\sqrt[3]{9}}{3}$
