Answer
$\dfrac{\sqrt[3]{3x^2y}}{xy}$
Work Step by Step
RECALL:
For any real number $a$,
$\sqrt[3]{a^3}= a$
Rationalize the denominator by multiplying $x^2y$ to both the numerator and the denominator of the radicand. Simplify using the rule above to obtain:
$\require{cancel}
=\sqrt{\dfrac{3 \cdot x^2y}{xy^2 \cdot x^2y}}
\\=\sqrt{\dfrac{3x^2y}{x^3y^3}}
\\=\dfrac{\sqrt[3]{3x^2y}}{xy}$
