Answer
$6-5\sqrt{x}+\mathrm{x}$
Work Step by Step
Use the FOIL method, along with
$\sqrt{a}\times\sqrt{b}=\sqrt{ab},\qquad$
$\sqrt{a^{2}}=(\sqrt{a})^{2}=a$ (for positive a).
$F:\quad 3\times 2=6$
$O:\quad 3\times(-\sqrt{x})=-3\sqrt{x}$
$I:\quad -\sqrt{x}\times 2=-2\sqrt{x}$
$L:\quad -\sqrt{x}\times(-\sqrt{x})=+(\sqrt{x})^{2}=x$
Add the terms (O and I are like terms...)
$...$= $6-5\sqrt{x}+\mathrm{x}$
