Answer
$\dfrac{3\sqrt[4]{x^3}}{x}$
Work Step by Step
RECALL:
For any non-negative real number $a$,
$\sqrt[4]{a^4}= a$
Rationalize the denominator by multiplying $\sqrt[4]{x^3}$ to both the numerator and the denominator. Simplify using the rule above to obtain:
$\require{cancel}
=\dfrac{3 \cdot \sqrt[4]{x^3}}{\sqrt[4]{x} \cdot \sqrt[4]{x^3}}
\\=\dfrac{3\sqrt[4]{x^3}}{\sqrt[4]{x^4}}
\\=\dfrac{3\sqrt[4]{x^3}}{x}$
