Answer
$s(-1)=0$
$s(1)=1$
$s(2)=\dfrac{9}{5}$
Work Step by Step
To find $s(-1), s(1), \text{ and } s(2)$, substitute -1, 1, and 2, respectively, to $x$ to have:
$s(-1)=\dfrac{(-1)^3+1}{(-1)^2+1}=\dfrac{-1+1}{1+1}=\dfrac{0}{2}=0
\\
\\s(1)=\dfrac{1^3+1}{1^2+1}=\dfrac{1+1}{1+1}=\dfrac{2}{2}=1
\\
\\s(2)=\dfrac{2^3+1}{2^2+1}=\dfrac{8+1}{4+1}=\dfrac{9}{5}$
