Answer
$f(2)=\dfrac{10}{3}$
$f(0)=-8$
$f(-1)=-\dfrac{7}{3}$
Work Step by Step
To find $f(2), f(0), \text{ and } f(-1)$, substitute 2, 0, and -1, respectively, to $x$ to have:
$f(2)=\dfrac{2+8}{2\cdot2-1}=\dfrac{10}{3}
\\
\\f(0)=\dfrac{0+8}{2\cdot0-1}=\dfrac{8}{-1}=-8
\\
\\f(-1)=\dfrac{-1+8}{2(-1)-1}=\dfrac{7}{-3}=-\dfrac{7}{3}$
