Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.1 - Rational Functions and Multiplying and Dividing Rational Expressions - Exercise Set - Page 346: 45

Answer

$\dfrac{x}{3}$

Work Step by Step

Factoring the expressions and then cancelling the common factor/s between the numerator and the denominator, then the given expression, $ \dfrac{2x}{5}\div\dfrac{6x+12}{5x+10} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{2x}{5}\cdot\dfrac{5x+10}{6x+12} \\\\= \dfrac{2x}{5}\cdot\dfrac{5(x+2)}{6(x+2)} \\\\= \dfrac{\cancel{2}x}{\cancel{5}}\cdot\dfrac{\cancel{5}(\cancel{x+2})}{\cancel{2}\cdot3(\cancel{x+2})} \\\\= \dfrac{x}{3} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.