Answer
$(2a-1)(a^4+3)$
Work Step by Step
Using factoring by grouping, then,
\begin{array}{l}
2a^5-a^4+6a-3
\\=
(2a^5-a^4)+(6a-3)
\\=
a^4(2a-1)+3(2a-1)
\\=
(2a-1)(a^4+3)
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 54
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