Answer
10x(x-11)(x-10)
Work Step by Step
Factoring the $GCF=
10x
$ results to $
10x(x^2-21x+110)
$. The two numbers whose product is $110$ and whose sum is $-21$ are $\{-10,-11\}$. Using these numbers to decompose the middle term of the trinomial results to
\begin{array}{l}
10x(x^2-21x+110)
\\=
10x(x^2-11x-10x+110)
\\=
10x[(x^2-11x)-(10x-110)]
\\=
10x[x(x-11)-10(x-11)]
\\=
10x[(x-11)(x-10)]
\\=
10x(x-11)(x-10)
.\end{array}
