Answer
$(3x-4y)(9x^2+12xy+16y^2)$
Work Step by Step
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of two cubes, then,
\begin{array}{l}
27x^3-64y^3
\\=
[(3x)+(-4y)][(3x)^2-(3x)(-4y)+(-4y)^2]
\\=
(3x-4y)(9x^2+12xy+16y^2)
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 24
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