Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 52

$2x(5x-2)(25x^2+10x+4)$

Factoring the $GCF= 2x $ results to $ 2x(125x^3-8) $. Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of two cubes, then, \begin{array}{l} 2x(125x^3-8) \\= 2x[(5x)+(-2)][(5x)^2-(5x)(-2)+(-2)^2] \\= 2x(5x-2)(25x^2+10x+4) .\end{array}