Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 33

Answer

$(b-6)(a+7)$

Work Step by Step

Using factoring by grouping, then, \begin{array}{l} ab-6a+7b-42 \\= (ab-6a)+(7b-42) \\= a(b-6)+7(b-6) \\= (b-6)(a+7) .\end{array}
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