Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 32

Answer

$(4x+3)(5x+2)$

Work Step by Step

The two numbers whose product is $ 20(6)=120 $ and whose sum is $ 23 $ are $\{ 15,8 \}$. Using these numbers to decompose the middle term of the trinomial results to \begin{array}{l} 20x^2+23x+6 \\= 20x^2+15x+8x+6 \\= (20x^2+15x)+(8x+6) \\= 5x(4x+3)+2(4x+3) \\= (4x+3)(5x+2) .\end{array}
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