Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 40

$x(x+1)(x^2-x+1)$

Factoring the $GCF= x $ results to $ x(x^3+1) $. Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, then, \begin{array}{l} x(x^3+1) \\= x[(x)+(1)][(x)^2-(x)(1)+(1)^2] \\= x(x+1)(x^2-x+1) .\end{array}