Answer
$6(y-3)(y-1)$.
Work Step by Step
The given polynomial is
$=6y^2-24y+18$
Factor out $6$.
$=6(y^2-4y+3)$
Rewrite $-4y$ as $-3y-y$.
$=6(y^2-3y-y+3)$
Group the terms.
$=6[(y^2-3y)+(-y+3)]$
Factor each group.
$=6[y(y-3)-1(y-3)]$
Factor out $(y-3)$.
$=6(y-3)(y-1)$
Hence, the factor of the polynomial is $6(y-3)(y-1)$.
