Answer
$4(k+4)(k+3)$.
Work Step by Step
The given polynomial is
$=4k^2+28k+48$
Factor out $4$.
$=4(k^2+7k+12)$
Rewrite $7k$ as $4k+3k$.
$=4(k^2+4k+3k+12)$
Group the terms.
$=4[(k^2+4k)+(3k+12)]$
Factor each group.
$=4[k(k+4)+3(k+4)]$
Factor out $(k+4)$.
$=4(k+4)(k+3)$
Hence, the factor of the polynomial is $4(k+4)(k+3)$.
