Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Exercises - Page 395: 20

Answer

$-(h+2)(8h-3)$.

Work Step by Step

The given polynomial is $=-8h^2-13h+6$ Factor out $-1$. $=-(8h^2+13h-6)$ Rewrite $13h$ as $16h-3h$. $=-(8h^2+16h-3h-6)$ Group the terms. $=-[(8h^2+16h)+(-3h-6)]$ Factor each group. $=-[8h(h+2)-3(h+2)]$ Factor out $(h+2)$. $=-(h+2)(8h-3)$ Hence, the factor of the polynomial is $-(h+2)(8h-3)$.
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