Answer
$(n+2)(3n-1)$.
Work Step by Step
The given polynomial is
$=3n^2+5n-2$
Rewrite $5n$ as $6n-n$.
$=3n^2+6n-n-2$
Group the terms.
$=(3n^2+6n)+(-n-2)$
Factor each group.
$=3n(n+2)-1(n+2)$
Factor out $(n+2)$.
$=(n+2)(3n-1)$
Hence, the factor of the polynomial is $(n+2)(3n-1)$.
