Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Exercises - Page 395: 11

Answer

$(2x-1)(3x-1)$.

Work Step by Step

The given polynomial is $=6x^2-5x+1$ Rewrite $-5x$ as $-3x-2x$. $=6x^2-3x-2x+1$ Group the terms. $=(6x^2-3x)+(-2x+1)$ Factor each group. $=3x(2x-1)-1(2x-1)$ Factor out $(2x-1)$. $=(2x-1)(3x-1)$ Hence, the factor of the polynomial is $(2x-1)(3x-1)$.
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