Answer
$2(4g+3)(g-2)$.
Work Step by Step
The given polynomial is
$=8g^2-10g-12$
Factor out $2$.
$=2(4g^2-5g-6)$
Rewrite $-5g$ as $3g-8g$.
$=2(4g^2+3g-8g-6)$
Group the terms.
$=2[(4g^2+3g)+(-8g-6)]$
Factor each group.
$=2[g(4g+3)-2(4g+3)]$
Factor out $(4g+3)$.
$=2(4g+3)(g-2)$
Hence, the factor of the polynomial is $2(4g+3)(g-2)$.
