Answer
$-(t-3)(3t-2)$.
Work Step by Step
The given polynomial is
$=-3t^2+11t-6$
Factor out $-1$.
$=-(3t^2-11t+6)$
Rewrite $-11t$ as $-9t-2t$.
$=-(3t^2-9t-2t+6)$
Group the terms.
$=-[(3t^2-9t)+(-2t+6)]$
Factor each group.
$=-[3t(t-3)-2(t-3)]$
Factor out $(t-3)$.
$=-(t-3)(3t-2)$
Hence, the factor of the polynomial is $-(t-3)(3t-2)$.
