Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Exercises - Page 395: 22

Answer

$-(11d-9)(2d-1)$.

Work Step by Step

The given polynomial is $=-22d^2+29d-9$ Factor out $-1$. $=-(22d^2-29d+9)$ Rewrite $-29d$ as $-18d-11d$. $=-(22d^2-18d-11d+9)$ Group the terms. $=-[(22d^2-18d)+(-11d+9)]$ Factor each group. $=-[2d(11d-9)-1(11d-9)]$ Factor out $(11d-9)$. $=-(11d-9)(2d-1)$ Hence, the factor of the polynomial is $-(11d-9)(2d-1)$.
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