Answer
$-(4c+1)(c-5)$.
Work Step by Step
The given polynomial is
$=-4c^2+19c+5$
Factor out $-1$.
$=-(4c^2-19c-5)$
Rewrite $-19c$ as $c-20c$.
$=-(4c^2+c-20c-5)$
Group the terms.
$=-[(4c^2+c)+(-20c-5)]$
Factor each group.
$=-[c(4c+1)-5(4c+1)]$
Factor out $(4c+1)$.
$=-(4c+1)(c-5)$
Hence, the factor of the polynomial is $-(4c+1)(c-5)$.
