Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Exercises - Page 395: 18

Answer

$-(v+3)(7v+4)$.

Work Step by Step

The given polynomial is $=-7v^2-25v-12$ Factor out $-1$. $=-(7v^2+25v+12)$ Rewrite $25v$ as $21v+4v$. $=-(7v^2+21v+4v+12)$ Group the terms. $=-[(7v^2+21v)+(4v+12)]$ Factor each group. $=-[7v(v+3)+4(v+3)]$ Factor out $(v+3)$. $=-(v+3)(7v+4)$ Hence, the factor of the polynomial is $-(v+3)(7v+4)$.
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