Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Exercises - Page 395: 3

Answer

$3(x+2)(x-1)$.

Work Step by Step

The given polynomial is $=3x^2+3x-6$ Factor out $3$. $=3(x^2+x-2)$ Rewrite $x$ as $2x-x$. $=3(x^2+2x-x-2)$ Group the terms. $=3[(x^2+2x)+(-x-2)]$ Factor each group. $=3[x(x+2)-1(x+2)]$ Factor out $(x+2)$. $=3(x+2)(x-1)$ Hence, the factor of the polynomial is $3(x+2)(x-1)$.
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