Answer
$8(v+3)(v-2)$.
Work Step by Step
The given polynomial is
$=8v^2+8v-48$
Factor out $8$.
$=8(v^2+v-6)$
Rewrite $v$ as $3v-2v$.
$=8(v^2+3v-2v-6)$
Group the terms.
$=8[(v^2+3v)+(-2v-6)]$
Factor each group.
$=8[v(v+3)-2(v+3)]$
Factor out $(v+3)$.
$=8(v+3)(v-2)$
Hence, the factor of the polynomial is $8(v+3)(v-2)$.
