Answer
$(2z+3)(2z-1)$.
Work Step by Step
The given polynomial is
$=4z^2+4z-3$
Rewrite $4z$ as $6z-2z$.
$=4z^2+6z-2z-3$
Group the terms.
$=(4z^2+6z)+(-2z-3)$
Factor each group.
$=2z(2z+3)-1(2z+3)$
Factor out $(2z+3)$.
$=(2z+3)(2z-1)$
Hence, the factor of the polynomial is $(2z+3)(2z-1)$.
