Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 15 - Sections 15.1-15.12 - Exercises - Cumulative Problems - Page 750: 139e

Answer

$pH = 1.171$

Work Step by Step

To calculate the hydronium ion concentration of a solution with 2 strong acids, we just need to sum their concentrations: $[HCl] = 0.0450M$ $[HNO_3] = 0.0225M$ $0.0450M + 0.0225M = 0.0675M = Total[H_3O^+]$ - Calculate the pH: $pH = -log[H_3O^+]$ $pH = -log( 0.0675)$ $pH = 1.171$
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