Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 15 - Sections 15.1-15.12 - Exercises - Cumulative Problems - Page 750: 137a

Answer

pH = 2.000

Work Step by Step

1. $HClO_4$ is a strong acid, therefore: $[H_3O^+] = [HClO_4] = 0.0100M$ 2. Calculate the pH Value $pH = -log[H_3O^+]$ $pH = -log( 0.0100)$ $pH = 2.000$
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