Answer
$pH = 1.260$
Work Step by Step
- Since $HI$ is the stronger acid, and it is in greater concentration, we can ignore the hydronium ion produced by $HF$:
$HI$ $0.0550M$:
Strong acid: $[H_3O^+] = [HI]_{initial} = 0.0550M$
1. Calculate the pH Value
$pH = -log[H_3O^+]$
$pH = -log( 0.0550)$
$pH = 1.260$
