Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 94

Answer

$\frac{\sqrt 3}{2\sqrt 2}$

Work Step by Step

$\sin\theta=\frac{1}{\csc\theta}=\frac{1}{\frac{\sqrt {24}}{3}}=\frac{3}{\sqrt {24}}$ $=\frac{3}{2\sqrt {3}\times\sqrt {2}}=\frac{\sqrt {3}\times\sqrt {3}}{2\times\sqrt {3}\times\sqrt {2}}=\frac{\sqrt 3}{2\sqrt 2}$
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