Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 74

Answer

$-7$

Work Step by Step

Need to solve $ 4 \csc 270^{\circ} +3 \cos 180^{\circ}$ In order to solve the given expression we can use Trigonometric table of angles. But $\csc 270^{\circ} =\dfrac{1}{\sin 270^{\circ} }=\dfrac{1}{\sin (360^{\circ}-90^{\circ} )}=\dfrac{1}{\sin (-90^{\circ} )}=-\dfrac{1}{\sin (90^{\circ} )} =-1$ Therefore, we have: $ 4 \csc 270^{\circ} +3 \cos 180^{\circ} = 4(-1) +3 (-1) =-4-3=-7$
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