Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 71

Answer

$-3$

Work Step by Step

Need to solve $\cos 90^{\circ} +3 \sin 270^{\circ}$ Therefore, $\cos 90^{\circ} +3 \sin 270^{\circ} = \cos 90^{\circ} +3 \sin (90^{\circ}+ 180^{\circ}) \\= \cos 90^{\circ} +3 [-\sin 90^{\circ}] \\= 0+(3)(-1) \\=-3$
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