Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 56

Answer

-1

Work Step by Step

The terminal side of $270^{\circ}$ angle passes through (0,-1). So $x=0,y=-1$ and $r=1$. $\csc 270^{\circ}=\frac{r}{y}=\frac{1}{-1}=-1$
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