Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 59

Answer

Undefined.

Work Step by Step

We can find the cotangent of coterminal angle that lies between $0^{\circ}$ and $360^{\circ}$ for convenience. $\cot 540^{\circ}= \cot(540^{\circ}-360^{\circ})=\cot 180^{\circ}$ The terminal side of $180^{\circ}$ angle passes through (-1,0). So $x=-1,y=0$ and $r=1$. $\cot 180^{\circ}=\frac{x}{y}=\frac{-1}{0}$ As denominator is 0, $\cot 540^{\circ}=\cot 180^{\circ}$ is not defined.
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