Answer
$1$
Work Step by Step
Need to solve $\sin^2 (-90^{\circ}) + \cos^2 (-90^{\circ})$
In order to solve the given expression we can use Trigonometric table of angles.
We know that $\sin (-\theta) =- \sin \theta$ and $\cos (-\theta) =\cos \theta$
Therefore, we have:
$\sin^2 (-90^{\circ}) + \cos^2 (-90^{\circ})=(-1)^2+(0)^2=1$
