Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 66

Answer

Undefined.

Work Step by Step

We can find the cotangent of coterminal angle that belongs to [$0^{\circ}$,$360^{\circ}$) for convenience. $\cot(1800^{\circ})= $ $\cot(1800^{\circ}-5\cdot360^{\circ})=\cot 0^{\circ}$ The terminal side of $0^{\circ}$ angle passes through (1,0). So $x=1,y=0$ and $r=1$. $\cot 0^{\circ}=\frac{x}{y}=\frac{1}{0}$ Denominator=0, $\cot 1800^{\circ}=\cot 0^{\circ}$ is not defined.
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