Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 54

Answer

0

Work Step by Step

The terminal side of $90^{\circ}$ angle passes through (0,1). So $x=0,y=1$ and $r=1$. $\cot 90^{\circ}=\frac{x}{y}=\frac{0}{1}=0$
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