Answer
$-3$
Work Step by Step
Need to solve $ 3 \sec 180^{\circ} +5 \tan 360^{\circ}$
In order to solve the given expression we can use Trigonometric table of angles.
Therefore, we have:
$ 3 \sec 180^{\circ} +5 \tan 360^{\circ}= (3)(-1)+5 [ \tan (270^{\circ}+90^{\circ}] \\= -3+5(-cot 90^{\circ}) \\= -3+(5)(0)\\=-3$
