Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 69

Answer

-1

Work Step by Step

We can find the cosine of coterminal angle that belongs to [$0^{\circ}$,$360^{\circ}$) for convenience. $\cos(-900^{\circ})= $ $\cos(-900^{\circ}+3\cdot360^{\circ})=\cos 180^{\circ}$ The terminal side of $180^{\circ}$ angle passes through (-1,0). So $x=-1,y=0$ and $r=1$. $\cos 180^{\circ}=\frac{x}{r}=\frac{-1}{1}=-1$
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