Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 83

Answer

0

Work Step by Step

$\tan [n\cdot 180^{\circ}]=\frac{\sin[n\cdot180^{\circ}]}{\cos [n\cdot180^{\circ}]}$ $\sin [n\cdot 180^{\circ}]=0$ and $\cos[n\cdot180^{\circ}]$ is always non-zero (equal to 1 or -1). $\implies \tan [n\cdot180^{\circ}]=\frac{0}{\text{non-zero number}}=0$
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