Answer
$=8-16+...+(-1)^{n+1}2^n$
Work Step by Step
$\sum_{k=3}^{n} ((-1)^{k+1}2^k)=((-1)^{3+1}2^3)+((-1)^{4+1}2^4)+...+((-1)^{n+1}2^n)=8-16+...+(-1)^{n+1}2^n$
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