Answer
$\{s_n\}=\frac{n}{n+1}$.
Work Step by Step
The pattern suggests that $\{s_n\}=\frac{n}{n+1}$ because the numerator begins at $1$, the denominator begins at $2$ and we can see that both increase by $1$ at each element.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 27
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