Answer
$1+\frac{1}{3}+...+\frac{1}{3^n}$
Work Step by Step
$\sum_{k=0}^{n} \frac{1}{3^k}=\frac{1}{3^0}+\frac{1}{3^1}+...+\frac{1}{3^n}=1+\frac{1}{3}+...+\frac{1}{3^n}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 53
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