Answer
$a_1=3$
$a_2=1$
$a_3=3$
$a_4=1$
$a_5=3$
Work Step by Step
If $a_n=4-a_{n-1}$ and $a_1=3$, then
$a_2=4-a_1=4-3=1$
$a_3=4-a_2=4-1=3$
$a_4=4-a_3=4-3=1$
$a_5=4-a_4=4-1=3$
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