Answer
$a_1=-1,a_2=1$
$a_3=2$
$a_4=9$
$a_5=47$
Work Step by Step
If $a_n=a_{n-2}+n(a_{n-1})$ and $a_1=-1,a_2=1$, then
$a_3=a_{1}+3(a_{2})=-1+3(1)=2$
$a_4=a_{2}+4(a_{3})=(1)+4(2)=9$
$a_5=a_{3}+5(a_{4})=(2)+5(9)=47$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 44
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